PGA Championship
![](https://images.ctfassets.net/56u5qdsjym8c/4w6WdFr1id7DEc5LXhf5bi/771f411c99594ab02aaef9941ba8d035/24CH_Valhalla_RGB.jpg?fm=jpg&h=200&w=200&fit=fill&fl=progressive&q=80)
PGA Championship Returns to Valhalla for a Fourth Time
The world's best players will once again return to Valhalla Golf Club in Louisville, Kentucky, for the 2024 PGA Championship. Set for May 16-19, 2024, this year's edition of the PGA Championship will be the fourth time Valhalla has hosted one of golf's most prestigious championships.
The last time the PGA Championship visited Louisville in 2014, Rory McIlroy was hoisting the Wanamaker Trophy, awarded to the PGA Champion, for a second time. It's the last time he's won a major, so you know he'll be a favorite. Tiger Woods won his second PGA Championship at Valhalla in 2000 in a playoff over Bob May, and prior to that, Mark Brooks seized victory in the same playoff fashion with his win in 1996 over Kenny Perry.
Aside from the three PGA Championships hosted, Valhalla also was the site of the 2008 Ryder Cup, where the U.S. Team claimed victory over Europe, as well as the 2004 and '11 KitchenAid Senior PGA Championships.
Event Details
May 16 - 20, 2024
Valhalla Golf Club
Louisville, Kentucky
Live | PGA TOUR
BMW Championship
Castle Rock, Colorado | Aug 22 - 26, 2024
A Piece of PGA History
The Wanamaker Trophy
The Wanamaker Trophy has been awarded to the winner of the PGA Championship since 1916. The Trophy is named after Rodman Wanamaker, who formed the Professional Golfers' Association of America.
Each champion's name is engraved on the Wanamaker Trophy. Jack Nicklaus and Walter Hagen's names are etched into the famous steel a record five times, while Tiger Woods name appears four times.
Woods and Brooks Koepka are the only players to successfully defend the Wanamaker Trophy in the stroke play era.
A Piece of PGA History
![](https://images.ctfassets.net/56u5qdsjym8c/6Z7ZiJZTAynyM36RqtUAY6/2e9e04a3eccca83c979a3418b50b6dc5/Wanamaker-Trophy-Hero.png?h=600&w=900&fit=fill&fl=progressive&q=80)